找回密码
 注册
关于网站域名变更的通知
查看: 491|回复: 1
打印 上一主题 下一主题

MATLAB基础教程之实例原文件 部分

[复制链接]

该用户从未签到

跳转到指定楼层
1#
发表于 2020-3-25 10:24 | 只看该作者 |只看大图 回帖奖励 |倒序浏览 |阅读模式

EDA365欢迎您登录!

您需要 登录 才可以下载或查看,没有帐号?注册

x
6 m- _$ p& ?5 G# v2 _
>> str=['MATLAB 2006a']) {) j7 I3 v* c! I

- [$ x, c# Q/ T8 K>> str+ L5 A; W, _' @# `: h) ?% O
! {/ c6 Q' g3 Y$ ^
>> disp(str)
& {% t1 W/ Z6 Q
9 j, f. e5 g6 o8 J; I%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%+ X" ^( h! ?# d& c0 P) {3 L, ^
* \9 D$ A- H9 T# k
>> x=-2:0.2:2;3 I: H+ z) x! ]" b7 X
- _$ \9 q- S: e( Z
>> y=x.^2;
8 U& e5 v: Z9 R+ g# {
; Y5 s" {0 A6 B0 m>> plot(x,y)5 x+ r) r+ j  C  J- n7 p2 ^( W( q

- j. ]' u+ o0 i& M0 ^>> str1 = num2str(min(x));9 o, Y! p$ w+ ^. j5 k
7 o9 k6 `( E  ]0 m
>> str2 = num2str(max(x));
* J, {1 v1 `; {# x% Y
3 O9 K+ Z2 t7 I* ~* ^>> out = ['Value of f from ' str1 ' to ' str2];! p! P$ W+ t. ?" h1 K( w

1 a, h# ~6 Y3 u$ K%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%56 ~5 I. r4 `/ `: P2 Z8 b+ H

, i$ E8 V  T$ s  s6 p>> A(1,1) = {[1 4 3; 0 5 8; 7 2 9]};( \6 c3 v' h" B" |3 }& e
! n' ]) Q% x; I5 r" z. D# q
>> A(1,2) = {'Anne Smith'};5 ^. s3 Z) E: j7 |

+ T# ]4 L6 E. Q; u' V+ a! s- D# [>> A(2,1) = {3+7i};
% `" I/ ~+ _/ v) B( r  I
- E5 L1 B1 i& k9 i+ D8 K5 n" W>> A(2,2) = {-pi:pi/4:pi}8 K! }  d/ M+ p- ?/ C
" [9 w- r7 p5 @; b  g1 ~
>> B=cell(2,2)& X& D7 E, @# \- }1 G1 d9 L4 h6 d0 x

$ `$ S4 W2 h; }>> B(1,1)=A(1,1)
' _# D* H0 X2 g( A% b6 E4 L  w>> celldisp(A)
+ x/ _1 Z( ~$ z, F/ L5 L3 D! g' [>> A{1,1}- T& {. E3 a3 J0 w- B: {' K
>> cellplot(A)* @& z( V) E/ p& S* Q0 D) a

9 x7 N$ |/ H* a# c# ?  }9 W, i! Z%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
* E6 z, v+ D/ c% p) S  [6 _& j5 @. a0 O# x5 y" D
>> clear
& e( D# r, u4 F* A; Z- tA=cell(3,3);" w# m4 L2 l2 H  A( \% U
for i=1:3
1 e. `1 z$ A' r    for j=1:39 u" [' Q. t' U0 o; i# m  j+ R6 S
        A{i,j}=randn(i,j);
/ M2 k- t& Z9 [1 a5 ?) a( F    end4 @( B, c* A9 o2 n
end) |! G" u. }8 g4 }
>> subplot(2,1,1)4 |1 C3 {: u- d6 Y
>> cellplot(A)
1 ?  d, e* ^: D* h4 ?. W7 z>> A(2)=[];" X6 u4 t% c% R
>> subplot(2,1,2)7 M# N) Q: T/ v
>> cellplot(A)
% D3 o2 H1 f. j8 S>> clear
& h. Q& P0 g6 jA=cell(3,3);
/ n+ \. d% j. O; g$ pfor i=1:3
& i2 d# S4 q9 h  z. ?    for j=1:3- `" n" |$ p3 E2 i* o- Z5 R6 x/ A. k
        A{i,j}=randn(i,j);
4 T4 w' W' w" a) Y" H+ S    end
8 l% C( u% U2 M9 o% Z( h/ kend
- W5 o' r  q3 ^>> subplot(3,1,1)( d9 z5 Z6 h: C# E% O3 l
cellplot(A)
$ n) |' S/ f. x# [: ~% LA(2)=[];
% ?! p- c" E" t6 O8 isubplot(3,1,2)- }4 ~2 h- E, h8 O; A4 J
cellplot(A)
; j1 v! s& f# R5 T9 H/ q>> A(3:5)=[];
, e: H8 n3 }% a6 s0 n1 w# t>> subplot(3,1,3)) E2 M* V* l' V/ L- D
cellplot(A)8 w: T( W' A4 \
  e3 H) z! n3 I) Y7 I; v* {
' E9 T6 K' d0 `: Q
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%( j: ?6 B; |% g2 r9 M1 H# Y* {
# o- O5 T* q) [# U
>> person.name='liuhuiying';
0 ^: G7 t9 }2 [2 j1 K; Z>> person.height=162;) B, v0 C  e/ P5 I& c4 [5 g6 w+ a9 C
>> person.weight=51;
( k9 T7 Z7 k: y% v4 H7 |+ u>> person.hobby='swimming';+ ?4 O7 X) F4 O3 K0 e
>> person5 ~( a* @7 a2 Y1 w

0 u+ c& t7 A! X! @" _) |>> person(2).name='zhangqiang';
1 |7 _; \8 t3 }/ C, D>> person(2).height=175;
( ~7 [( E6 u8 S  ?3 j>> person(2).weight=65;. e) V$ _/ b' J# Q$ V, C- i
>> person(2).hobby='Game';6 ]0 |& \% k" u; ]+ t, X
>> person
8 h: d6 Q% O$ J$ _# g% V7 F  Z7 l8 X( @) e
>> person(1)
% Q# W- Q1 O) t7 e( N9 C
7 a; c( ?3 U* I1 y2 U# y% `>> person(2)
6 d* m' S0 ~/ F) x( o) `# F: H1 f$ b4 Z7 r1 p. `
person =
. v2 O6 [1 D3 |% ]+ Y4 S# d2 a- Z% d# r" a# S
      name: 'liuhuiying'
, F6 Z9 {. e: U, C    height: 162; |, a0 R) T/ ^% W
    weight: 51
; ]% B5 O5 s+ W: j# h2 i     hobby: 'swimming'
9 L; {" M# Q2 Y% d" E
, C5 \- J- f: N1 R/ J5 E
5 x+ W/ ~! R3 X1 Z0 e( q  Bperson =
; ~! q; n& Y. R
6 \+ r& [2 s. t4 L% c1x2 struct array with fields:
+ U1 n: u! y7 B8 H; W! b; _1 f    name8 L: Q" z' j  E) _* W! p" I
    height' X6 q) K6 {( S2 _9 t; V
    weight
: t) I' Z( o) P) U* J    hobby  C! C) t$ s- P0 A# a8 t1 r; H2 j

2 q1 Z9 X; F9 j7 \, J' V) E% S8 S2 C$ H  p
ans =% v! Z) a- k& a4 D

4 F+ j% ]/ Y9 Q! @7 P( `      name: 'liuhuiying'
, }4 V5 i: Q6 s" C    height: 1626 }& L+ u( F5 \( u) l& n
    weight: 51: w' I. R! R0 C3 e
     hobby: 'swimming'; V: V7 V: H. R: x* ?
  T  i* y$ T3 J0 ?

3 f% s7 m" G1 y& q) jans =' l- C$ y4 h6 r0 i0 m# C; m

- [; g" u0 s5 f7 ]      name: 'zhangqiang'
4 y# |6 c" x& q) p! A    height: 175! C$ t8 Z3 Z$ {4 \+ i
    weight: 65
* ~" |+ o$ d3 w2 \     hobby: 'Game'
7 i4 D) @) f$ e# `. |
* n, _- M7 y: A8 e" g* H9 {1 S%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
9 g6 X% c/ ^% g2 o3 }* C; B' t6 e" T; d4 k, T" j3 B
>> person=struct('name','liuhuiying','height',162,'weight',51,'hobby','swimming')' a3 i8 s% P2 |
1 O! `3 M# z" r1 R8 a, m- p
person =( }% g0 G/ D# @6 D+ T
8 C' ^* U2 y: v' g8 x6 r- O
      name: 'liuhuiying'
! c5 d; K: A% H1 \; i( `    height: 162
) Q. R% j; X5 h( B/ O/ k) L    weight: 51, ^! Q/ F, M+ \/ ~  Z
     hobby: 'swimming'
3 F5 T* S0 [, H  s0 v
$ s. l8 J2 h6 G; e7 F%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%, ^0 e% K" V6 c( R' Q% G

( v# G; ^, U0 F7 L( r, j>> person=struct('name',{'liuhuiying','zhangqiang'},'height',{162,175},'weight',{51,65},'hobby',{'swimming','Game'})
, Y+ n* k3 c7 V( B
0 Y) Y) u) n( W9 E* w>> person(1)
* l' M" c" p+ o& c0 y# _& m; ^0 ]' j- I; ~( N, O
>> person(2)
' F+ j8 F- t. Z! y  _1 \- v, `8 \, }8 f2 U$ J; F( P7 [

. ]- m! p+ [& ]- \4 y1 @7 k4 O( f, A. G# s- x1 ~
; D. d) i( v$ E9 E; m& U
person =
( a6 Y0 j+ y) Y: E  Y# i- f4 g
  _8 W% Y- `  _' o* V1x2 struct array with fields:
) p% v0 Z7 J4 }9 {    name
( B1 H& W% I! s5 R3 E% j7 u# z    height1 G. z; q* W$ Y7 m& H
    weight
) s4 G7 Q' U" S' H4 R# \1 o& |( Y    hobby7 x6 N5 @1 U9 Y7 \+ I; b
3 o0 H! k6 W% r3 M9 {

: Y$ _0 C$ E7 Gans =
3 Y, [& @/ A2 V! s/ Z7 K4 w  _. @3 D! ~' r  N
      name: 'liuhuiying'
/ n4 G4 M, t4 B2 ~+ W7 e    height: 162
" R; u# _/ B+ T6 F/ o  l    weight: 517 ~3 l4 |+ t/ a. r! |4 D
     hobby: 'swimming'" t! I/ U- i( f% E! k+ ~
- \, w8 [. L5 x1 }: Z
3 b5 _5 ]3 H# U6 \* j6 ]: J4 ?
ans =+ q! S( U8 f: v3 M8 [
! K, k0 B  W2 Q, K( g
      name: 'zhangqiang'/ x# @" i7 p7 G6 C
    height: 175
  t& J9 A9 b. g8 F9 K+ V1 I    weight: 65
( x: d3 A0 o- k1 t* d# n1 P     hobby: 'Game'
2 k# `5 Q; t# F% T; V( Z) T/ z# P+ O* I/ H2 b$ f+ F0 U( `) c
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%50 |, a  Q$ w. u0 j; n

+ r. }8 d  t+ F6 c6 T9 P/ R>> person(1).gender='female6 s( O) W: b# H. h# `" y
' F# W2 X0 N7 \1 r
>>person(1)
1 s* p8 F( c, h8 a4 b5 W/ k' {1 Q( E0 n
>>person(2)
, S% L) F) {) M* I4 H8 h" t* }: g5 L! T  H& X8 M+ e
person =
9 q& I( n) }: a- g7 _; T( u
( {8 w: W. n- K8 ^" a+ Y1x2 struct array with fields:
- C9 A, U8 T: W5 F    name5 c( P4 A6 o+ f6 i
    height
0 e) Q( Z0 h* G. H    weight
  |" D* f: u5 r  e* W( B    hobby( ]0 j. J; L+ h$ n
    gender! }, ^% }3 {0 x/ R' Z, T, ~. ]

/ X9 M0 ^5 ^) [9 F$ S2 M5 Q5 h; Q# K$ z) L9 J4 q) q
ans =" f; g! Y/ |8 G6 |
: E& K3 {% t' j4 m
      name: 'liuhuiying'
$ l: I0 M8 |  s5 }" r    height: 162$ m" N2 S; z) o! }& M
    weight: 51
6 l, x/ M& h: x6 f/ U' _; O# C     hobby: 'swimming'5 c! }) p+ N+ |
    gender: 'female'- ^6 ~4 f* S" X
2 O7 `" E9 c6 z' k
  q1 w- D4 H9 j% M& [( [% Z
ans =
/ h+ ~" S$ O; G2 n+ b& X8 ]
4 e* O0 y4 N4 Q+ B% `      name: 'zhangqiang'
' A- {1 e2 W9 r  o5 s, }- |    height: 1757 [. h9 b, K" a; i. @
    weight: 656 T. P2 b9 D: e! S- {, E/ V$ A
     hobby: 'Game'
+ B! w; p1 `2 N: h3 h1 I% g# A    gender: []0 B4 g4 ~5 Z, \' I4 f% Z; P
+ ]% F9 e+ v6 Z* v2 ?
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
) [( ^7 z' E! H% A7 \0 O, ^
5 h( h8 q& j" P" g7 Z>> person=rmfield(person,'hobby')9 h9 @# y: O! X% `, H/ ]
- r7 ?! f! ^- {6 F
>> person(1)& `" j% S' w' n% `

) K+ {2 p+ t7 h, O9 x& L>> person(2)
! x" J# S* Q! N: j- W) @7 P9 ~8 ?. p* u5 Y; O
+ r. L, X- x' b7 s* R; J2 w3 }
* D0 R2 M' u0 J
person =8 x$ |) f/ h5 E; h
; n: [" K6 Z2 S' y# u1 p
1x2 struct array with fields:
2 q, w8 M& k) V# [$ r    name5 T+ L0 J' u' `/ W6 l9 `1 B
    height9 i5 p4 e+ {, W( j& k  r
    weight4 l4 I- z' l- j3 W; X/ P! }
    gender
- a5 p0 q3 |# r+ |2 i- Z! D: N% _
, W# |& ?+ l7 B, I' h2 w6 G
/ B6 |1 x% v6 t/ Fans =
, O& _8 ~8 y! d& o& B
( r! X9 W- ?$ y! l3 ^% ^      name: 'liuhuiying'
) F5 b+ r8 k- H  T    height: 1623 I( Z$ t; \+ _6 X* M4 _* D: O' j
    weight: 51. g+ q! E- o9 N! P" g
    gender: 'female': A% V& e- [5 C! K( U6 b! h

, S! l% U1 K& v& v- N2 o% B8 m* T& j8 N  ?  |  {
ans =
+ h* j/ r2 W* r7 M1 \% l9 c4 E  z' U) n. O( H- }
      name: 'zhangqiang'3 E: h* o8 L" u+ S5 t  V- ]
    height: 175
9 o. _. [. o; b2 j# @6 L" ?4 ]! W    weight: 65! i" \" c4 i' V/ s, L  _7 H2 u. z; R
    gender: []
, a& _) a. L. @$ v+ G
$ `( l1 i9 c6 [2 M
5 y* I7 |3 v3 j* t, |2 z2 M/ V6 h* ]9 H
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5" Z$ c( b/ A; W* e

2 L9 z9 p( o) ^3 S- c& z2 g+ `>> person(2).gender+ W" P" C$ h7 T( R5 U5 C

" C, g- Y- Q9 Z5 I>> person(2).gender='male';% w; B/ o- d% @  U4 W* G0 G

$ C' V& i. {! Y( h: Z' `>> person(2)
; v9 S' W- }! L8 c1 ]6 H0 T( z1 U
5 u7 B$ X. C: r; ]
/ k8 d( B# L* \% `/ \6 z
# l5 E( H3 y8 K2 P0 Fans =# S) D* x$ f9 V/ v9 E! b, i! _/ l  Q

  @$ g8 U$ u( R& j8 [     []
9 e! F, I! v. C9 y$ C4 f- A: Q
% P7 |4 S! {! o) Y
' G3 Y! |8 i9 ^+ H+ I  J% Rans =2 B( g. i8 {9 N2 N% o$ }! P% |3 Z
9 e% O- |' E: ?6 ^1 x6 u% M1 h
      name: 'zhangqiang'
2 U% V$ b$ P, F% ^: n1 n  R5 }* U' T    height: 175
# o) U0 w, k/ g1 [    weight: 65* P5 v2 M6 O. q5 e7 x
    gender: 'male'( X( _  f6 M. i. [. d
9 B% U. y. S4 E7 a6 ~* j9 L
* o* }5 d; j* ]
$ P4 O5 t1 ^, X7 @0 O/ L
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%51 H# d/ }0 Y% V0 N) \

2 I5 v5 ?! b2 O$ q9 w$ K>> A=[10 20 30 40 50]
/ Q) x2 s- z% Q+ f$ l
% v. u) @( @0 B3 ~4 ?5 P>> B=[10;20;30;40;50]
' a2 h) L: _# `/ F
& d9 v" E5 I; ]" ^8 ~7 X%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
& Z+ |+ f  M+ @  e- R3 a9 l+ G7 |+ O
>> A=1:2:88 B; [5 `) e6 t

( s5 |6 |4 P  g6 u>> A=linspace(0,12,4)
; u6 c% g) @$ p( Z7 f+ Y* L/ [5 H4 D6 ~. b' ]: M8 I7 [
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
6 G$ \2 C' H2 e/ F9 V- z+ ~! i) n: ^- f+ N- t
>> find((A>8)&(A<14))       %找出矩阵A中大于8并小于14的元素的单下标索引6 B. J, J; a# P1 s7 f

% W8 G1 W6 Q2 w# K>> A(find((A>8)&(A<14)))    %找出矩阵A中大于8并小于14的元素
3 @& H6 ?% c- B" r4 U: p" p1 t
2 j( P7 M& G/ ~6 O0 [3 B6 u5 r%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
2 F* Y) k% r' f8 N# T) f9 y: Y  K. z  b; D
>> A([1,3,6,8])0 [& G( _( D& l; K% f7 a5 W

4 e6 b! }  p6 a6 k+ E' W7 b/ w%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%56 R2 v1 m4 Q: a3 I
4 C& d6 Y) s- ^2 |* A  C8 w
>> A=rand(3,3)
1 Q* Y& ?- L$ U& W% N" O. r- H- V6 T' U! E8 X5 E$ Y
>> A(:,:,2)=randn(3,3)
+ |# s5 R. S7 M' M  V7 P1 x' i2 w+ i8 l1 n* I9 h1 C, z8 B$ R: C
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%53 ~6 J. ~: \/ d- v2 e

/ I/ l1 m: x6 M; M>> A = rand(5);1 X) |- b$ w2 ^- L! n
- H; R$ C2 Q' B0 t; L$ e" o/ o
>> B = A > 0.5;3 o6 J+ g. u2 y

, @( ]( d- a. \' N" z) |* L>> A(B) = 0
8 f) X5 G: y# n) a5 [: C& ~
: r" f) Y# T7 J7 X' F/ E % ~) y/ O+ H: n5 i! p8 I
2 Q! B0 D9 }/ K$ p; i8 w
A =; Z9 k* l8 V. w2 |3 t! T
1 \* I: {8 i* \2 ]
    0.1450    0.4018    0.2400    0.4909    0.1112
9 J! e. X. |" W% ?7 E& p" O& X         0    0.0760    0.4173    0.4893         0
& y+ c' q2 U2 F6 E% L: I+ s         0    0.2399    0.0497    0.3377    0.3897
- h# f3 W6 ]. y) z  L* ]' _2 h    0.3510    0.1233         0         0    0.2417, C2 i- y# g! c5 [! l; w( `" J
         0    0.1839         0    0.3692    0.40391 f8 J8 _2 o5 `' Y/ o7 P
7 i+ P$ A9 V/ a0 d
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
; D1 ~& K! k5 `7 L; H9 t7 n3 B4 w- E0 U
>> A = magic(4)
- N. K4 R  Y! k; ]- k4 }$ p
- Q. e7 v6 p, @/ d, S: q- ^>> B = isprime(A)  Q2 I, ~' ]. c. x& W

; A6 p! V6 ~$ F: ~3 e5 u>> A(~B) = 0
$ L0 N, k- q) [* q
  O, c4 e% O4 } . o' L/ H# B, f! I$ \5 n

0 S) f7 H: [; V% K6 E. T# g%%%%%%%%A =
- {$ w, w8 U# a* _) S" V% g& J+ Y2 S; H' D( @
    16     2     3    13. J& q" c% R8 h: R; y% \
     5    11    10     8
; g. f# L4 W( ?1 s* e: q+ I( R( B     9     7     6    12$ C% S  l& Z5 G$ C1 `
     4    14    15     1. C/ }6 I7 |4 P# o6 U7 ?
2 R- Q5 q' y% k
: O3 J$ c5 Z( i, Q
B =
- V0 x0 H- A, j& O
/ B3 \) H+ h* E; D6 I3 D1 s0 I4 W     0     1     1     1
- ]. c% V0 Y2 Q     1     1     0     0- o5 e# C& R& l% M5 P" S' g
     0     1     0     0; c3 W/ {5 r9 b7 D
     0     0     0     0- k: d- H: W# e1 Y
$ o# W! s1 i, g) ?
0 V) Q0 z3 p, d5 h( J  m
A =+ a) E4 R2 P/ R) f) V% n
% h& A) |2 y! |4 f: T! E# U
     0     2     3    13
1 k& m1 z4 s# M1 C/ E     5    11     0     07 {5 U, \4 ]+ o7 e, u
     0     7     0     0' \! T! s6 a' b
     0     0     0     0
; o+ a( j$ ]9 }+ t/ |  _5 w- a
9 f' ^: |, [% N) z: B; u%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5) U: P2 [. o, c

+ U2 W) ?0 O, H >> r=[1 3 5];
4 H% x- F% A. I' |, |
$ G  @* |' t3 d3 `% g>> p=poly(r)
/ n8 J9 N* A% W: X
" h4 t. ^* o# P& o' F2 I8 S>> poly2sym(p)
9 q% t  ^; Q9 A% [: q
4 u$ k0 P9 Z. F* t7 f5 e4 h) t>> roots(p): d8 r' a* u- O) v! q" H! S

0 p2 v% P: Q, r6 s' e3 v) o. kp =
, C, {% s, S( m" j; G6 A+ i: D( A& D# _( E
     1    -9    23   -15. C' B  R8 n$ w& S

( k( ?" l4 `0 q/ K ) ]$ I& ?  P3 S# |& C: Y' Z+ y. x
ans =
% A9 r2 ]" y; Q
$ K- |2 W7 Q) ~/ b( R- m: Sx^3 - 9*x^2 + 23*x - 155 w6 a; U) \0 E6 }
, E( i1 v( K3 S9 v$ K7 Q# C

  U5 y5 D" Y& w9 v9 C  R- yans =% C2 G* \$ q# w& c* G
2 s4 z1 e* r7 }. e
    5.0000. U2 C3 t; j/ U4 s$ k) Z
    3.0000
. O* E  e0 K" G$ f    1.0000
! v) c, n  B  h/ f( y/ u4 q  `1 I0 q' c
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
, {1 L6 G& u+ O' K: h; Q
. Y- \( z' N2 {- ]>> p=[4 3 2 1];
4 `" |7 G# u8 v
* I! n1 l0 {- S3 G>> polyval(p,4)5 i$ u" b' l9 `) K$ m0 B

& V9 g1 O0 Y0 z: h4 i>> 4*4^3+3*4^2+2*4+1
. d; w0 R& W5 k( _" P
# d4 W: Z  b8 u) ~$ q  }; c: w
) w* \8 D+ C7 l, ]3 x7 P9 H* Tans =
1 ]4 M0 I6 P6 T3 @0 k9 W, E
+ C' ?1 p( B, o" w3 Q; Q   313
, p( C( G9 D" D! ^3 H8 ~' w7 v& K
! }* P# a+ B2 ]$ f  Q5 \% H  v9 s
# B- u# e  ^2 P& Nans =$ [: \* Y9 f$ w5 U; e

( \2 M: o- X" }1 _# \. G+ w   313
8 U) g; o! w% w) |$ J" H2 ^( |" k6 _
, M9 u! F! i- r$ r7 F; L5 P' g%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
* ?! J  E* J8 X/ ~$ E5 w5 T. B5 [1 r+ |
% fit sine between 0 and 2*pi using 3 order polyn0mial  ?. N4 [: K( i
x = 0:pi/10:2*pi;) J" a1 ~8 K+ e) C' o& Q
y = sin(x);
  Z# L7 o# b; Y* `( q1 Xp = polyfit(x,y,3);! J' d  f9 ~5 j
plot(x,y,'r*');
( B$ p! Y* x8 @1 y7 T: W; thold on
1 ]: D' i5 E- j* tf = poly2sym(p);
  f3 y0 f# J8 F! s: E2 ^& ?ezplot(f,[0,2*pi]);
1 R! c/ }. N5 b. i6 [( g* g9 {6 u% O/ Z* r9 M
>> p; y  I( }' ?  }. u
$ v' f4 `' F1 C: j$ l4 g

4 Y3 e. _, v$ p( ^8 H# a2 a+ u+ I& K8 Y( {: Y# w
) J; P0 r9 T9 ^' p2 u4 h8 r5 v# Z
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
/ C1 ^6 ?; N0 n  ]" [
, z- R6 [5 s) H2 T% Interpolation using the four methods
% d8 U) r5 q) m% v1 {" Lx=[0 3 5 7 9 11 12 13 14 15];
, ]6 d" Z5 R& O& X5 X: j* N( y; Vy=[0 1.2 1.7 2.0 2.1 2.0 1.8 1.2 1.4 1.6];
7 s1 C9 r) ~7 y. t' l3 clength_of_x=length(x);
/ w% ^' N. e/ |. d: {& C. dscalar_x=[x(1):0.5:x(length_of_x)];
- v3 z+ G' v% b' g" S. {  j- mlength_of_sx=length(scalar_x);
5 @9 `( D; @2 A6 H1 O1 e  L, O0 R, ofor i=1:length_of_sx
. T  I4 u7 u, H/ B% R& u# z' C    y_nearest(i)=interp1(x,y,scalar_x(i),'nearest');: Y; F, a/ D+ _( T) h+ p+ I
    y_linear(i) =interp1(x,y,scalar_x(i),'linear');
) |0 a2 W. W$ U1 C& @; u    y_spline(i) =interp1(x,y,scalar_x(i),'spline');( S8 I, m  r+ k( Z. q
    y_cubic(i)  =interp1(x,y,scalar_x(i),'cubic');8 u4 @9 M/ F- h# q
end( n* b- b  U5 R6 P; p; [
subplot(2,2,1),plot(x,y,'*'),hold on,plot(scalar_x,y_nearest),title('method=nearest');
6 c" _- E( i, d+ S8 H; V6 N5 ^subplot(2,2,2),plot(x,y,'*'),hold on,plot(scalar_x,y_linear),title('method=linear');3 y9 P+ i! P5 p  d$ W/ [
subplot(2,2,3),plot(x,y,'*'),hold on,plot(scalar_x,y_spline),title('method=spline');0 h& i# {2 d% T  \, b
subplot(2,2,4),plot(x,y,'*'),hold on,plot(scalar_x,y_cubic),title('method=cubic');
5 J; c& N) z8 k3 N
, }& `- Y. B) r% `8 n# w$ J: f , I. C9 p! \1 O/ V3 R
, @3 R$ B. x+ i* W/ x

/ H0 o6 |) P0 c9 Q; K%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%57 n" ~1 G3 X# p4 m* Z/ V  x7 q

! C% C9 e$ f, ?  e2 z+ g2 P>> fh = @(x,y)y*sin(x)+x*cos(y);+ ~/ x% A- P0 J
/ |" D, M6 c( v8 k& w* f* l" j
>> fh(pi,2*pi)5 C/ i9 d) i: o" s- f8 H6 O3 |

1 w, Y9 h9 U7 A4 W* {%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%5
' j, R1 Q0 R# t0 ?0 A
. e$ ]) Z, q5 k8 c2 v4 p fh = @humps;/ R1 k5 K! p3 m: A% @5 k: g
/ B( z$ A; G8 M
subplot(1,2,1),fplot(fh,[-3,3]);
6 f* J: i- c3 F7 f( s/ ?6 V1 }  r; r+ p0 {$ Q. `
subplot(1,2,2),fplot(fh,[-3,3,-10,30]);$ ?1 x; U5 {6 O) S/ W

( g+ S( }5 `: G+ z: }%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%50 P* \+ D9 w8 Q* ]
, h( j, K2 G5 \3 z

0 x$ H4 u0 o/ X5 m3 E7 m; J' {7 }  {2 [" W# G+ p
% find the minimum of the function f(x)=x^3+a*x^2+b*x+c6 y: B" B# Q/ s8 b/ T
function [x0,y] = funmin(a,b,c,x1,x2)
- J! h9 m: R$ coptions = optimset('Display','off');
  Z! y* o& }" K3 e3 r[x0,y] = fminbnd(@poly3,x1,x2,options);
# A( @. F$ W5 |3 {3 h    function y=poly3(x)        %the nested function/ l! l5 m& V- A) G
        y=x^3+a*x^2+b*x+c;
) \0 g: \5 X% C* v5 C' p$ ]    end: o$ j3 h( |+ L, W# E
% plot the function2 f$ K, }* @1 ^& e( ?( Y  |6 }
fplot(@poly3,[x1,x2]);
. {6 e5 o- V5 s8 Bhold on;% j. }( k- {3 R& R8 _2 |
plot(x0,y,'.');
8 I- e, O' }& send
7 m/ w  G' L" }8 N; X) l2 E6 p- y5 N) P. K) l
>> [x,y]=funmin(-1000,10,0,600,800)
9 E) h0 A2 A2 [: ^% i( o& M( z  @) y/ ~4 Z& S' {
& {! ^  C8 D+ f
0 e9 v0 e8 h4 X
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
. U6 r  R3 z0 ?: R
( t1 c. \2 P7 U>> F = @(x,y)y*sin(x)+x*cos(y);
6 g/ G* M0 q" c) t2 }  Y; i7 L0 c% X9 I/ _* O
>> Q = dblquad(F,pi,2*pi,0,pi)0 v  t4 t) B! z4 e
% Q2 j2 V5 H2 N) K3 R  Z) D7 H
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
" m( l# l8 _( n) w- t) J$ d7 z' @& p' E" p0 |% n7 g* X) W4 X: ]
>> h_g=@(x,sigma2)exp(-x^2./(2.*(1:sigma2)))./sqrt(2*pi.*(1:sigma2));% F/ D' Y" {+ F9 C" j( q; e! q
! p' Z( p; F4 `2 g
>> quadv(@(x)h_g(x,3),0,2), t3 i8 z) u9 h2 v
7 r4 z' x2 x" \* n2 b) H: r
ans =, x6 h" S! Y4 \" N

$ H1 u9 W4 N. E  i    0.4772    0.4214    0.3759) x$ [: a- B3 K. d5 c" R$ U

9 u6 ^1 y+ l3 i1 C; r9 L' v>> quadv(@(x)h_g(x,2),0,2)
, ?  u8 X& ~8 U& C3 J# y  S0 H! \3 F; u0 k7 `+ ?+ }- `! X+ f
ans =" _$ ~7 h% W! a9 ?2 w. T" O7 Z

+ \( m/ Q- e! m    0.4772    0.4214! D# q' c/ c- t" a- M8 G% P# \; x
6 w5 {/ P  H3 n! d! P
>> quadv(@(x)h_g(x,1),0,2): ^7 L! a, j' L/ l

8 X( q" [% ]4 a/ q) N( F' sans =
& L/ ~$ C$ d" z6 u* ~' x+ @2 c
: Q) s3 ~4 O2 ~) ^    0.4772
4 N! \: c8 t7 O- {7 A3 e; w. |; S4 v
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%& S& t' U& y: `) ^, L' B) t' n

3 o( T5 b& O) S3 f* `2 j9 f% the file to creat a function with parameters
+ B, w9 n8 W7 |9 Ifunction y = poly3_fun(x,a,b,c)) f# M# }. L" [0 L! s
y = x^3+a*x^2+b*x+c;
) E/ ^. H8 x9 T: @  D
0 u# {( ~5 I5 T/ h) Z% L; S& b4 [7 h9 m  d
% find the minimum of the function f(x)=x^3+a*x^2+b*x+c
( N  Z; ~8 b0 R% gfunction [x0,y] = funmin_para(a,b,c,x1,x2)' h3 H. {6 E1 H, O6 H
options = optimset('Display','off');
( }7 j0 B1 g$ R& \[x0,y] = fminbnd(@(x)poly3_fun(x,a,b,c),x1,x2,options);4 I  F) k+ N, \& Q
% plot the function
! Y) {# _7 e. K$ P7 [end
) R5 y& U% h# r. i6 ]8 v' I3 _, n2 _6 s8 W7 T: H6 C" V
2 g8 ~) T) a5 V! W
>> [x,y]=funmin_para(-1000,10,0,600,800)
! D. [! X2 G  c/ |* `. ^* a; N; l6 S) Y$ D
& Q3 {2 Z" l5 V

/ z& T) N, U1 M4 b/ A%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
* U" R1 u8 S! `; \/ ]% t  d( O  b( |+ R! t# d0 E% v+ G- z
: Q, g" n! ~3 K3 l/ n% a" p0 a
- B2 v( Q" Q- R% a, u0 i* ]
% polynomial operation
" y) U6 {5 H) m4 s8 bp1=[1 2 1];                         %定义多项式5 {+ b  s9 a6 D, ]' u
p2=[1 1];% |* ^# t$ a) t8 O# e& H; P2 W: j
length_of_p1=length(p1);' H$ Y6 ~7 p1 l  ~7 j1 L
length_of_p2=length(p2);! J* V6 _9 T# B( m. j
if length_of_p1 == length_of_p2     %判断两个多项式长度是否相等* n* K8 b; N) A; T" [0 u
    p1_plus_p2 =p1+p2;              %多项式相加
* ^; z5 v( M0 d7 a. j6 @! F    p1_minus_p2=p1-p2;              %多项式相减
5 ], g3 L9 M8 O( Xelseif length_of_p1 < length_of_p2
6 k, [1 Q( j, e7 h        temp_p1=[zeros(length_of_p2-length_of_p1) p1];
8 Q( c" O7 A" n* j+ b& s        p1_plus_p2 =temp_p1+p2;
! j5 E/ J1 e6 r  U! K3 n- ~* A        p1_minus_p2=temp_p1-p2;
0 q: m5 d/ J2 R7 o3 m- O- }else1 Y+ t' i; h- E3 o/ T
    temp_p2=[zeros(length_of_p1-length_of_p2) p2];. \2 h% V8 L6 E
    p1_plus_p2 =p1+temp_p2;; Y( v" ?: Q/ T5 ^: b; u% R
    p1_minus_p2=p1-temp_p2;
! X) e' O3 G0 eend
7 P2 b! m$ I" h" f+ s+ V  ^p1_multiply_p2=conv(p1,p2);         %多项式相乘" R* H! }: D  |8 R' ~7 P
p1_divide_p2  =deconv(p1,p2);       %多项式除法& j% [) n; Q1 ~
p1=poly2sym(p1)                     %显示多项式 p16 G1 o8 V; {/ `
p1=poly2sym(p2)                     %显示多项式 p2+ u* t6 W1 |4 |3 v
p1_plus_p2 =poly2sym(p1_plus_p2)
( ]% Y3 E5 F! W. R9 Rp1_minus_p2=poly2sym(p1_minus_p2)/ w* \: ]8 M- L2 ~( d- N# b% v
p1_multiply_p2=poly2sym(p1_multiply_p2)
: N' \1 y4 ~$ s/ n- op1_divide_p2  =poly2sym(p1_divide_p2)$ \8 p/ r: }2 n8 B

# }9 E( L6 |5 j9 b& B
" X8 @2 |4 r) W9 R1 d. i& n5 z( O& G. C
7 ?5 a" m' @, p  ?' D  y , W; O: {$ V' L# ~
/ k6 b8 e9 ]6 q1 s% i' {1 j$ U& z, z# T

& w0 ]6 u( u( i4 F. h/ p
* S( E4 }9 {) K) z' up1 =$ k  }. |+ Z, L. p8 X9 D8 a

: K- o# K1 z/ {0 j" Gx^2 + 2*x + 1
: H3 X$ ^4 u: ~/ Q( {
& O$ P+ _8 Y& }; h   f( Z5 L! n" z1 G. G4 |% ^
p1 =! S3 s: n8 R2 C% y, T
( m1 I! y5 V! z# Y# S8 s- G; [
x + 11 B  Q  I' u8 r. v/ _. O# d8 X

, [" c1 x( y9 C  K; r . H3 T( |# |  [6 G1 _& x
p1_plus_p2 =
2 e3 e8 ?* ?. o% g3 T
  f+ k4 o1 D; q# R( ~x^2 + 3*x + 24 p$ n9 t  K" W0 @
1 i& w) L0 h7 r1 c, u0 @

. e$ Z: m& o- Z* d4 S3 @p1_minus_p2 =
; O8 J( U0 T% v3 j % t* Y) H1 H8 _2 i
x^2 + x# l2 _& l" g7 _: [" Z  x3 a
) F, y- X9 Q& E! U( G. L
. C0 i& R( r5 {2 S$ [! z  i
p1_multiply_p2 =
# H- A/ D! B7 Y% I+ w2 W/ X ( O' ^# R0 W5 S  d7 s; N! I
x^3 + 3*x^2 + 3*x + 11 {- J# B5 i4 {- D$ ^8 ~

" ]# @7 b, D6 B) r+ l
! h8 P* ]: L- R& @/ \% w( gp1_divide_p2 =
# N" n6 h  E. j# c0 x) q
! S. S2 O  {8 {5 o4 ix + 16 ]! O2 D" p# k+ O! e" T
. H$ m( `" [5 h, D. `
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%+ j( W& R; E' A1 S1 @
0 D3 w: D7 y* J# x* s

% E) H) z5 p8 W8 F
; [, \+ D/ G8 b& [% i2.编写一个脚本,判断输入字符串中每个单词的首字母是否为大写,若不是则将其修改为大写,其他字母为小写
' U: k% w3 H* U) Q
7 @4 P1 I5 x1 Z2 f7 u, N参考答案:% z8 j6 u; E( E6 x6 @2 p
0 u! e+ K3 @1 X1 a
脚本文件内容为:
) |, \. u) f) F6 G( ]. o) e
( G3 x5 s  \5 ^; t, mstr = 'this is the string to be converted';
9 M' o% z$ ]# ^4 E- @' C6 c" S
) e' l+ A* w/ I$ [5 Pnlength = length(str);& U) T' M! X" P: c- E4 N5 {8 l
! f3 f9 t. g* _
for k=1:nlength
9 m5 a8 }* m, A8 Y* w
) @3 b. ^* Q% O# w- R: t3 J    if (k==1 || isspace(str(k-1))) && (str(k)<='z' && str(k)>='a')0 e4 j" g/ o. @0 ]; [7 Q  K+ }

  _/ \- ~! C% L+ J( `1 m+ w% [4 S        str(k) = char(double(str(k)) - 32);
# N. K! \, A- y! l, |/ B  y
' o/ ?+ v) R( E& W1 u3 S5 u    end$ R) B4 R! n( O* b+ C. s% ]

. h' f! m$ r9 x: ~+ Lend, u# ~& K* W* h7 t5 i
0 N3 I  v& a, v! S" y6 ]# Y
disp(str);+ _# \7 r$ H4 I- L. D( Y2 G3 U
: `2 s. o; f9 W& L+ j3 \; A

; m0 i4 \0 U' ?4 {0 Q, t( e
1 g8 A1 N2 K+ D' g%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
0 L, B4 W; r- M: B- G3 O' A6 [) M( G& r: q% D% u
4.创建一个结构体,用于统计学生的情况,包括学生的姓名、学号、各科成绩等。然后使用该结构体对一个班级的学生成绩进行管理,如计算总分、平均分、排列名次等。
$ U6 O1 M( ^9 |+ d2 c8 m
/ t# O, ]. p1 Z- [7 C; s; p参考答案:5 C5 C9 N. G3 q6 W/ o1 N' e

* @1 s, y1 F" X>> structtest=struct('name',{},'number',{},'scores',{}); \, ^* Y# p) p) L3 Q  `

: [  {# L- ]6 w2 ?8 K " f1 f* ?' i0 M8 e. V+ z, B

0 D8 F( L' \" m%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
& x! r+ R- j* }: m4 d8 B
) U, e, z' X' |/ A! z1.创建符号表达式
! {8 C! k6 j9 E/ V4 U- E$ B: t9 d: F$ O+ W3 v: r* r* {0 Z/ Z9 _7 C
参考答案:
1 {1 |1 D6 @9 z4 N+ Q. ?7 l
) N$ t) }5 [- ~8 ~>> f = sym('sin(x)+x');/ ~. F5 b3 E: W+ f& ^
! z- H1 x: j. Z# x: e" f8 {5 _
2.计算习题 1 中表达式在 、 、 处的值. V: k5 t/ _7 n, h
; F" P7 t% x8 M9 b1 b* Q; I
>> subs(f,x,0)6 z8 K7 o3 J/ _/ W5 k' T
+ D0 [& F4 Q6 F1 |3 c1 R
ans =( A7 w$ r5 h+ p% N1 c& x) k

5 \0 J1 m/ _0 M/ {     0
+ A, H2 w' B6 g0 y3 h7 u, f" W" b; V9 C
>> subs(f,x,pi/4)
3 E3 L9 a8 L9 }( C/ |' E" B  u7 `% q9 \$ ?
ans =7 ?5 m) B- k- Z6 G. ^& K' R  ~
' @" B3 e: m6 X# k& w3 s3 V
    1.4925" ^) C6 @1 x/ y, f

* S6 V4 q/ }& A* B: v2 D* u& U " S0 e" P4 ?, Y( C5 H; ^

- H5 z9 Q+ x+ ~: Y% Q%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
* F. {1 K1 }% ^8 i+ X& \* Y& X  J$ C. e
xth = 0;, k0 |8 U. i) `  L: F8 `
tic
. B9 X# V' j0 O% Sfor x = -10:0.5:10
6 c  P- K' y4 n0 Y# I* m    xth = xth + 1;
* R* S3 h% l2 m0 {. g3 c    if x <0
% [' R$ g2 [1 C2 D        y(xth) = -x^3 + 5;2 {) M3 e! `; ?" U+ ~
    else
9 L# u% |( z' u3 `" {$ u( Y3 y        y(xth) = x^3 + 5;
3 u; \, `1 w/ V8 X3 r( Q    end
, [+ i% w; q5 v' V$ T- T# wend
$ b9 L( `5 k6 k3 rtoc
; L/ d& t% _1 z$ ?5 j  q% }5 _  e8 c0 n5 W" t9 \% S9 v
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%$ _# _3 f& @& ~
2 z4 }9 P) c' c* e* z+ g% Z1 a
tic- G; T- K. |, i0 X! O
x = -10:0.5:10;
* I2 Q' ^( d* Z3 Ly = zeros(1,length(x));* N4 u8 w  n$ V! B
x0 = find(x>0,1,'first');7 y/ B9 F- {9 B- s- V3 U4 I* f
y(1:x0-1) = -x(1:x0-1).^3 + 5;0 ^9 B/ X0 \0 X0 i- y
y(x0:end) = x(x0:end).^3 + 5;
" L' \% B! \( M) |# {0 ~toc
: ]1 |. ]+ s( Y2 \+ ^, @9 T- m0 h; t3 d# c+ r% i# `6 ~) o2 C
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%8 V+ f9 ~" [6 u' W

- o8 I; e' v  Y+ R8 B6 d* a9 z$ O ' c: r+ l4 e( S- M! I- {
2 Z2 _. `3 j# v  @2 E
1. 在同一窗口中绘制函数在 之间的正弦曲线和余弦曲线,步长为 ,线宽为 4 个象素,正弦曲线设置为蓝色实线,余弦曲线颜色设置为红色虚线,两条曲线交点处,用红色星号标记
( ~: J; s/ g3 T7 H, y$ A/ p, n
! q) i* b, L1 Y& e参考答案:
7 V2 Z' U4 Y) e8 g" v/ ]/ `- d2 u3 a& {2 T( R
>> x=0:pi/10:2*pi;
  l0 G) ?+ k8 @- b, `% T) K+ T6 v) v' B3 U* Q) k' C) \
>> sinx = sin(x);) o% \: u5 n' k$ G. ]* {; c2 B

; e7 p, y; N8 a8 a: [5 c& C/ O>> cosx = cos(x);; p4 i/ E! G2 ?; X; T' T: h

6 `& ?$ U5 ~) t0 L>> figure,plot(x,sinx,'LineWidth',4)
- m- e3 T; l+ r1 H6 i* q
  C$ U3 B9 g7 r2 b8 T>> hold on,plot(x,cosx,'r:','LineWidth',4)3 v2 ^0 m1 {( }: u0 _
5 Y7 }7 |+ w9 p6 i+ N
>> hold on,plot(x(find(cosx==sinx)),cosx(find(cosx==sinx)),'r*','LineWidth',4)
+ S" K4 ~  K2 ~: d3 L, Q3 g" Q) r' s/ X  L( g& E, A) Z" Q
% l! ^. U6 Y% n+ x3 n# y
# y+ a. P5 s, [0 s- N! w. e
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
6 X/ w! x6 o  n. n: Q4 W" V  V8 R4 k
% l2 u& S+ @# r1 \- c0 Z: C( r  ^; u1. 编写 MATLAB 程序,绘制下面的函数:
1 ]) g; C5 k$ p5 a/ f  Z& N& ^% H6 G. K3 c4 S$ v! u- l* F; b- h
,其中8 g% W5 j# O; e2 b

% ?7 C& H6 ]0 v3 O该程序在绘制图形之后等待用户的鼠标输入,每单击其中一条曲线,就随机修改该曲线的颜色,包括红色、绿色、蓝色、黑色和黄色。7 {" K5 S+ ]5 q! _/ v
" v" U4 x& A: A
参考答案:
0 T, T/ S+ }/ p0 U* e2 y# t. W0 z: Y, t" N& [
t = -2:0.1:2;" l8 x  A" p- e  \/ S/ \' V
( M, A- r* i' ?6 y
x = cos(t/pi);
" f- `9 r: D8 o$ Y. o- ?* o- @; F
y = 2*sin(t/(2*pi));
. J5 j3 v! g! u4 D- p$ R% c, c# f5 j( i& S, _5 q
figure,plot(t,x);
7 G+ l% {. ~! O& X
. n1 F+ t7 U# Nhold on; plot(t,y);% h- U  ?7 Q, }8 S) A

& L4 W) M$ ^6 l, ~* r7 B%if waitforbuttonpress1 u% z# N( U# M) W

' B! g% m0 O* O) D# P. E5 S& pwhile(1): ]7 g, E. U3 }

2 e- S; M6 {& \8 D! M! Q( ]    if waitforbuttonpress==0
! U' w) O1 |8 h+ L
5 X3 f$ [( |7 u% X1 F. J        get(gcf,'CurrentObject');1 l. h, l5 A; a7 X$ }! ^

' F* |2 ^9 i6 L( f' W, [        c = ceil((rand) * 5);. k: G1 t6 u7 A9 `

+ g! W: j  s. K; p. ^        switch c
2 {( Z& \5 w. T5 A
8 i" j7 _$ h, Z, k8 a            case 1
  E% `  W& ^& J6 A) k
, @6 J. D) T, t# R  L4 V  @                set(get(gcf,'CurrentObject'),'Color', 'r');' _, ]2 [3 k: }) |2 P

" e4 }( e& d. S* ^  `            case 2
0 i; P# C( d, M0 k( G: h. |# Z
" W. B: m/ B3 Z3 I! y  L4 ^2 I0 s2 ~                set(get(gcf,'CurrentObject'),'Color', 'g');" E" v; T1 N# O: D0 Q$ g
% ^" l( N$ u' t
            case 3* \5 U+ i" v+ H" F: ?0 u

1 e; v3 U$ K+ B7 G0 S) Y$ H                set(get(gcf,'CurrentObject'),'Color', 'b');" K  x0 t% e* f5 x6 D

6 e. ]3 B7 L. U' j- E& Z( Z            case 42 b3 e0 Z8 d0 G6 f, V4 `
3 O: P7 e' w7 i4 g6 f( ?# d
                set(get(gcf,'CurrentObject'),'Color', 'k');
6 l" l2 h+ d: u$ m$ W. R6 O+ l, z, k
            case 5
/ K) K5 |) W; B+ |$ E8 n( l9 s6 }1 }( h0 |9 j) [$ N/ s3 _
                set(get(gcf,'CurrentObject'),'Color', 'y');
; W0 v. V4 d# ]' t/ U1 w( ]; [- m0 D0 M2 i+ Q
        end
) N5 v# J# z: ^5 o8 G# K  B/ y6 u$ x. O  S
    end
7 }4 b/ A$ u: V3 j0 T9 O0 i
, J- M% Q% i) B7 `8 l7 X- rend
$ u6 p6 T+ u, g  P4 z7 I+ C  B  [6 n
8 l- S4 K% q( _3 U

2 X" U2 \3 F1 `: t5 i
9 f0 X- C  }6 Q+ J/ n, O- {- w1 R( W

该用户从未签到

2#
发表于 2020-3-25 17:56 | 只看该作者
MATLAB基础教程之实例原文件 部分
您需要登录后才可以回帖 登录 | 注册

本版积分规则

关闭

推荐内容上一条 /1 下一条

EDA365公众号

关于我们|手机版|EDA365电子论坛网 ( 粤ICP备18020198号-1 )

GMT+8, 2025-11-2 19:41 , Processed in 0.218750 second(s), 26 queries , Gzip On.

深圳市墨知创新科技有限公司

地址:深圳市南山区科技生态园2栋A座805 电话:19926409050

快速回复 返回顶部 返回列表