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我从TI的官网上下了一个INA331的库,自己建好添加后,进行Pspice仿真。结果出错了,我看了很多教程,都没用。应该不是添加的问题,可能是破解的问题,因为TI的工程师都没能搞定。" P+ k# n) V8 E: T4 J
下面是错误信息。
3 U' Y" ~- Y- |/ u, r+ k3 g**** 07/30/10 20:21:36 ******* PSpice 16.3.0 (June 2009) ****** ID# 0 ********
" [$ [+ R8 c1 r8 B7 C5 a** Profile: "SCHEMATIC1-ina331" [ F:\ina331\ina331-pspicefiles\schematic1\ina331.sim ] $ _6 ~7 t4 ~0 O7 `! b+ B5 r
3 t# w; S# Q0 r" `* W
**** CIRCUIT DESCRIPTION
) |- F- O4 d% v0 x7 D. N! Q' {) v! f3 x; N _6 f* ?$ }) K6 I
******************************************************************************
! |) J0 O% c* i4 H( [; F7 C5 c9 ^% s: ^) M2 u h' y- C
( B \' W5 d; v W( Y% X' p/ ]
** Creating circuit file "ina331.cir" $ U3 G) U$ N# l1 V- {
** WARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE OVERWRITTEN BY SUBSEQUENT SIMULATIONS
) j! V" E0 b! `* {5 L) c B*Libraries: ' W- ]9 X: i0 A8 r
* Profile Libraries :
5 e% j0 M5 K/ G, C9 Z; |* Local Libraries :
: ^5 H1 r7 K" i: F* From [PSPICE NETLIST] section of F:\cadence\SPB_16.3\tools\PSpice\PSpice.ini file:3 \- @/ h0 t2 h- v% U
.lib "F:\Cadence\SPB_16.3\tools\capture\library\Userlib\INA331.lib"
3 k9 t u- g) T3 Z. E*Analysis directives:
. e- S: I" k6 ?7 ~.TRAN 0 1000us 0 2n
, G9 g9 Z: Y! ]( T.PROBE V(alias(*)) I(alias(*)) W(alias(*)) D(alias(*)) NOISE(alias(*)) : R2 h U3 d0 O; w" p3 r& S
.INC "..\SCHEMATIC1.net" # l) X( G/ M% T* M9 j- x% S
+ I4 L6 u# G) x* U
**** INCLUDING SCHEMATIC1.net ****8 u3 v+ K( T+ y4 j5 X! w0 _+ d: i* n
* source INA331
2 j. U; C e! lR_R1 0 N00576 40k / R7 Q5 z& c6 w
R_R2 N00576 N00608 40k & ]1 `: K, m6 g5 n* i `2 t
R_R3 N00608 0 150k
0 k# U& T. K( S% X' o5 gC_C1 N00576 N00608 3p
0 v' h# Z" G+ B5 |+ F7 Y0 R5 jV_V1 N00453 0 5
; p/ A* |1 P# S7 ]' P7 s! rV_V2 N00352 0 2.5
( M# i P* |$ M2 e6 oV_V3 N01435 0 4
6 H# C3 s9 {7 C$ A! JV_V4 N01420 0 1.25. k/ @( M1 U: h
V_V5 N00361 N00352 $ f0 w4 L4 O* ?# a
+SIN 50mv 0 100k 0 0 0
, j( G8 z+ g% HX_U1 N00576 N00361 N00352 0 N01435 N00453 N00608 N01420 INA331
: c2 u& |+ _8 U* b( h" g**** RESUMING ina331.cir ****6 A1 I: |2 h. z6 [3 @/ [$ t/ c
.END
: y0 U# n; N) c$ O) e
8 R) p+ B, C6 j**** EXPANSION OF SUBCIRCUIT X_U1 ****
8 L* ^, z3 j& D) ?& y5 p% [X_U1.C48 X_U1.192 0 280P
. |; P# m- k' Z7 c1 N. AX_U1.R187 X_U1.88 X_U1.82 39997 TC1
5 ]5 O7 z: G+ N/ [--------------------------------$
) V9 Q* Q7 b6 x: XERROR -- unknown parameter
/ z* C1 y$ z5 B8 a$ } C) U+ 800E-62 Q4 D: B+ [/ e2 F3 |9 v4 b' e
X_U1.R188 X_U1.23 X_U1.88 10E3 TC10 o+ d$ g8 ~9 d# X. S1 z9 x' e
-------------------------------$
* |$ B0 A/ w- G" c E: {5 |ERROR -- unknown parameter
' U6 o* ^# ~! \5 x8 r @$ J+ 800E-60 E, i. F A+ C4 ], d; h" q
X_U1.R184 X_U1.29 X_U1.23 10E3 TC1* A: A6 h7 H; `1 b
-------------------------------$
& G) H/ r) f6 A/ nERROR -- unknown parameter5 S5 q2 T# d' E1 F4 `" M+ `+ R
+ 800E-69 \# W2 K R; ]9 K3 J" w( ]; l
X_U1.R185 N01435 X_U1.29 40E3 TC12 A; q' b: [9 f1 Q
------------------------------$
' o* z. y9 y; k5 }6 e kERROR -- unknown parameter$ F& N5 r4 d$ _3 y5 A+ G+ F# O. C
希望有能解决这一难题的中国高手。 |
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