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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?
    5 N$ G) N3 e/ K
    - c4 N% r3 ?% a, t5 ]If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
  • TA的每日心情
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     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the& _. |' t' V9 g; w) K7 F* y
    assertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the0 q( R( N" g3 v
    issue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
    1 Y0 J5 }6 f/ _4 {4 _  Q( q- X; m$ Noutput of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
    * R: j2 s2 ^' W& ^, [, e* n$ }0 FAnother problem that an asynchronous reset can have, depending on its source, is spurious resets
    # X6 H$ f6 [: I$ a5 {due to noise or glitches on the board or system reset. See section 8.0 for a possible solution to* S6 [( i' _3 \' c8 x
    reset glitches. If this is a real problem in a system, then one might think that using synchronous" T% q1 q9 }. b, Z2 S. D
    resets is the solution. A different but similar problem exists for synchronous resets if these2 j& u, M1 I* L) D( }
    spurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is
    8 y0 C8 I) q6 D0 [4 P* qtrue of any data input that violates setup requirements).
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