PCB线宽与电流（PCB line width and current）

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PCB 线宽与电流(PCB line width and current)
The withstand current of 1 square copper wire is 5 -- 8A, 380V can
! f/ k4 X1 u3 o* rbe brought with maximum 4KW, 220V can be maximum 2KW.
2 square? Three square meters can be pushed like that
3 Q$ p2 z1 ~% @/ o( J( P" Q; NPCB line width and current relationship
, |) i  P" f- |; [" bI. calculation method is as follows:
First, the section area of Track is calculated. The copper foil
3 }1 S5 k; _& h+ B( rthickness of most PCB is 35um (the PCB manufacturer can be asked if it
is not certain). The width of the PCB is the
) c# o' b4 O9 P" g' gcross-sectional area. There is an experience value of current
3 ~( R8 m9 T: w- |density for 15 ~ 25 amperes per square millimeter. We can just call it
% a- d; W: c' g6 N; Lthe area where we get the volume.
7 A; H/ e. _/ T  P1 v! M1 d3 d; TI = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the
1 x" G: _9 Z' z, F" C' q* u$ Cinner layer of the copper line, and 0.048 in the outer layer)
  ^7 q& z4 t) k, e) _, q" D: KT to the maximum temperature rise, the unit for degrees Celsius
+ n. i5 i) ~. y( I4 l% h(copper melting point is 1060 ?)
A to cover the area of copper, the unit is square MIL (not mm mm,
the attention is square MIL.)
I is the maximum allowable current, the unit is ampere (amp).
The average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,
& }* i% ^5 [# ?$ a8 U5 `which is 8.3 A  

# ^" H0 {. b1 l6 J" c

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PCB线宽与电流

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学习一下，谢谢。
+ K7 C6 ]- @' i/ M" p+ z