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% page 151 3
! h& p* r! b, a1 f/ Z% 写出一个插值多项式
: M" L" `$ H8 H, r% input :vector(x,y),interpolation point x0
/ |7 K3 o! Y) B2 u) h' k% output:the result at x = x0
; z+ U4 I& Z& T9 Lfunction y0 = page_157_1(x ,y,x0)& p3 c# |, d4 _$ X
format long
# ?9 S. P, F; m# }5 [9 ?5 Pn = length(x);. @6 O' r4 e, e' o B
for j = 1:n %fill in y colum of Newton triangle
L% Z& S2 U7 k# C* y% z9 o- Z6 \2 | v(j,1) = y(j);
p/ e8 r5 B" O+ iend0 s# U3 q& ^( r+ H3 ~% ? |# U
for i = 2:n %for colum i: E) v# P3 g- \
for j = 1:n+1-i %fill in colum from top to bottom
: ^' Q, ]: i' ]2 D9 u4 v1 M v(j,i) = (v(j+1,i-1) - v(j,i-1))/(x(j+i-1)-x(j));1 N m1 o2 B- I; b# |
end
4 N% n: B' w; yend, i6 N) t0 H# `6 h, q5 h6 x1 Y4 B
for i = 1:n
% T" L& c( S4 F! C+ [4 Z- X v(i) = v(1,i); %read along top of triangle $ p+ P0 r* s) ?6 f* X. y
end %output coefficients" K# R' r0 m7 @3 h. d' O1 ?
y0 = v(n)*(x0 - x(n-1)) + v(n-1); %initial nest8 K+ b1 n" e" k8 @6 y5 i
for i = 1:n-2 %use nest7 |6 _9 {% H4 q5 U* u* \
y0 = y0*(x0 - x(n-1-i)) + v(n-1-i);! W$ B3 O$ _2 f, ~
end
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