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我用一个调用函数来计算一个区间上的函数值并画图。此调用函数的输出是x = [x1; x2; x3];我想要把三个值的图像都画出来,编写的plot语句却都错了。错误信息: p2 c0 r# R; I6 W5 W7 W
错误使用 plot。
7 x/ b% d9 e) \2 j& U数据必须为可转换为双精度值的数值、日期时间、持续时间或数组。/ ]/ O0 m+ E3 ^
% |% c8 M' |; p3 Y出错 Untitled3 (line 3)
- A( T: u* c$ @ q$ E/ ?; ^plot(y,c(:,1));$ k7 P" l# k' @! Y: G1 W$ w9 S$ `
7 z+ W) u' C$ N/ u9 \以下是程序,使用的64位R2018。$ k, U6 v8 C* M7 s, G
y=9.9:0.01:10.1;9 x2 ~( k7 y0 f5 N. v
c=Solve3Polynomial(1,2.*k-20,power(k-10,2)+0.00005,-0.000001);3 `& {9 p, e) B# ^8 T# k+ g
plot(y,c(:,1));0 u7 s: h( ?# r+ |. F
plot(y,c(:,2));* ]8 C7 J* [( N0 N1 I
plot(y,c(:,3));7 D0 R: a3 R1 T2 x& ?5 m9 B
function x = Solve3Polynomial(a,b,c,d); X: G+ S1 z( p/ p# d0 A( y
% 范盛金. 一元三次方程的新求根公式与新判别法[J]. 海南师范学院学报,1989,2(2):91-98.
1 E5 S: \' f* c- W# t2 Lsyms x1 x2 x3;3 |8 H9 a- | Q K# y2 G& V
A = b.*b - 3.*a.*c; if abs(A) < 1e-14; A = 0; end7 F/ l8 i5 m7 r2 u$ e$ g
B = b.*c - 9.*a.*d; if abs(B) < 1e-14; B = 0; end% O+ Q# }" ^7 f% d5 o; e& Y
C = c.*c - 3.*b.*d; if abs(C) < 1e-14; C = 0; end
; W7 q6 L8 \ Y4 F5 p! dDET = B.*B - 4.*A.*C; if abs(DET) < 1e-14; DET = 0; end ! ]7 n9 [ r: ~) R
if (A==0)&(B==0)
k) q P5 Y3 [1 b9 H! w0 j x1 = -c./b; x2 = x1 ; x3 = x1;. |) k) {. d i6 c$ L9 K
end# B, x- D" R A0 r$ Q- w# l# r* h5 Y
if DET > 0# B: h. Z) s% Y) }
Y1 = A.*b + 1.5.*a.*(-B + sqrt(DET));
6 y+ y2 W/ l# z* C Y2 = A.*b + 1.5.*a.*(-B - sqrt(DET));
2 ^2 \! K7 e- R% \8 z4 R- M y1 = nthroot(Y1,3); y2 = nthroot(Y2,3);% `, |" g+ O. j7 W5 }% _
x1 = (-b-y1-y2)./(3.*a);) k( y$ G& I- [, R- `
vec1 = (-b + 0.5.*(y1 + y2))./(3.*a); ' E0 f" q( Y7 V/ L
vec2 = 0.5.*sqrt(3).*(y1 - y2)./(3.*a);; c+ X8 I- ^) L
x2 = 0;3 U% A/ b& c, b# D4 p! Y, ~
x3 = 0;% F/ E+ h9 T1 v* l: K
clear Y1 Y2 y1 y2 vec1 vec2;
* U+ i9 N% e" n( {1 a. |$ tend1 A- }; W1 q9 d5 }! ^( W0 t
if DET == 0 & (A ~= 0) & (B ~= 0)) y3 I7 s5 @2 f6 H. Y
K = (b.*c-9.*a.*d)./(b.*b - 3.*a.*c); K = round(K,14);- X7 Y: x8 H$ J* `: r! b
x1 = -b./a + K; x2 = -0.5.*K; x3 = x2;
5 q; T; J% t) k" l/ ^end
8 h; `" [. c0 H+ G1 Bif DET < 0$ J) k; x6 s7 h* S3 F9 D
sqA = sqrt(A);
0 I' Z6 M6 l/ Z T = (A.*b - 1.5.*a.*B)./(A.*sqA);
& l9 G8 P( J' ]" p/ L: u! e theta = acos(T);, ~7 O& o4 Z7 ]2 p8 M) @; ?5 f
csth = cos(theta./3); `2 h3 v: ]& \/ Z7 a, o) U
sn3th = sqrt(3).*sin(theta./3);% ^& ?% l) i! v0 l6 f
x1 = (-b - 2.*sqA.*csth)./(3.*a);
* @! G$ p4 u" e2 H/ {# k1 _. p x2 = (-b + sqA.*(csth + sn3th))./(3.*a);8 _" W$ v' t0 n9 P: n: [$ ^
x3 = (-b + sqA.*(csth - sn3th))./(3.*a);- H- g# A. w1 J* s1 D* B# p
clear sqA T theta csth sn3th;- {0 j$ X, ~! l% \, f" ?& r
end) d% e6 F9 J# v& P8 m
x = [x1; x2; x3];) E. {8 }- N. _$ `
end
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+ }0 x h! P, w, h- Z麻烦大神帮忙指点一下,非常感谢! |
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