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EDA365欢迎您登录!您需要 登录 才可以下载或查看,没有帐号?注册  MATLAB语言并未直接提供曲面积分的现成函数,因此,此处给出计算曲面积分的函数。
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 应用举例
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 # I8 e6 r! k' x' ~1 [, B' b第二类曲面积分
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 function I = suRF_integral(f,vars,t,a,b)%surf_integral%第一类曲面积分%   I = surf_integral(f, z, [x,y], [x_m,x_M], [y_m,y_M])%   I = surf_integral(f, [x,y,z], [u,v], [u_m,u_M], [v_m,v_M])%  Examples:%  计算int_int(x^2*y+z*y^2)dS, 积分曲面如下:%  x=ucosv, y=usinv, z=v, 0<=u<=a, 0<=v<=2*pi%  MATLAB求解语句%  syms u v; syms a positive;%  x=u*cos(v); y=u*sin(v); z=v; f=x^2*y+z*y^2;%  I = surf_integral(f,[x,y,z],[u,v],[0,a],[0,2*pi])%%第二类曲面积分%   I = surf_integral([P,Q,R], z, [x,y], [x_m,x_M], [y_m,y_M])%   I = surf_integral([P,Q,R], [x,y,z], [u,v], [u_m,u_M], [v_m,v_M])%  注意:I = int_int_S(P*dydz+Q*dxdz+R*dxdy)%  Examples:%  计算曲面积分int_int(x*y+z)dxdy, 积分曲面如下:%  (x/a)^2+(y/b)^2+(z/c)^2=1的上半部,且积分沿椭球面的上面。%  引入参数方程:x=a*sin(u)*cos(v),y=b*sin(u)*sin(v),z=c*cos(u);%  且0<=u<=pi/2, 0<=v<=2*pi 。%  MATLAB求解语句%  syms u v; syms a b c positive;%  x=a*sin(u)*cos(v); y=b*sin(u)*sin(v); z=c*cos(u);%  I = surf_integral([0, 0, x*y+z],[x,y,z],[u,v],[0,pi/2],[0,2*pi])& c$ U( ]7 x. w( q3 K
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 第一类曲面积分8 r) k( y8 _* G5 f' W0 W- I6 q
 1. 计算
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 syms u v; syms a positive;x=u*cos(v); y=u*sin(v); z=v; f=x^2*y+z*y^2;I = surf_integral(f,[x,y,z],[u,v],[0,a],[0,2*pi]); Y1 }2 i0 t% p0 R5 k4 T( L9 h
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 2. 计算曲面积分
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  的上半部,且积分沿椭球面的上面。7 i# O% g; Q2 J% F 注:引入参数方程:
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 6 A8 I& L) l/ Q1 `8 l5 h5 h7 S, Gsyms u v; syms a b c positive;x=a*sin(u)*cos(v); y=b*sin(u)*sin(v); z=c*cos(u);I = surf_integral([0, 0, x*y+z],[x,y,z],[u,v],[0,pi/2],[0,2*pi]); o$ Q0 W7 N! O
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 $ X1 {2 @; O8 I# O6 [" n" Rfunction I = surf_integral(f,vars,t,a,b)if length(f)==1    if length(vars)~=1        E = simplify(sum(diff(vars,t(1)).^2));        F = sum(diff(vars,t(1)).*diff(vars,t(2)));        G = simplify(sum(diff(vars,t(2)).^2));    else        E = simplify(1+diff(vars,t(1))^2);        F = diff(vars,t(1))*diff(vars,t(2));        G = simplify(1+diff(vars,t(2))^2);    end    I = int(int(simplify(f*sqrt(E*G-F^2)),t(1),a(1),a(2)),t(2),b(1),b(2));else    if length(vars)~=1        A = diff(vars(2),t(1))*diff(vars(3),t(2)) - diff(vars(3),t(1))*diff(vars(2),t(2));        B = diff(vars(3),t(1))*diff(vars(1),t(2)) - diff(vars(1),t(1))*diff(vars(3),t(2));        C = diff(vars(1),t(1))*diff(vars(2),t(2)) - diff(vars(2),t(1))*diff(vars(1),t(2));    else        A = - diff(vars,t(1));        B = - diff(vars,t(2));        C = 1;    end    f = f(:); abc = [A, B, C];    I = int(int(simplify(abc*f),t(1),a(1),a(2)),t(2),b(1),b(2));end) i7 o/ b2 j2 V: t
 
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