II2C总线芯片 24c0x读写程序

Demyar · 发表于 2019-1-4 09:40

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II2C总线芯片 24c0x读写程序
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#include<reg51.h>( F0 z7 w2 N& }  m3 O! R( M
#include"intrins.h" //  _nop_();
/ _9 W2 R) g  W, ~% y5 k% K1 K#define uint unsigned int8 q8 z- Y3 M! X, c* M
#define uchar unsigned char
& W& E( d3 h4 Bsbit scl=P2^1;# d( ]5 v" M: q  R! f3 H
sbit sda=P2^0;
- ]- a7 w, K6 h( X7 a/ ~$ Ubit write=0;+ o: R: w$ q( J5 n) n$ s
uint num,num1;
3 y% g7 |9 S! m, ouchar ge,shi;- ?* y  @/ S$ I0 u! a$ L
uchar code table[]={0x3f,0x06,0x5b,0x4f,0x66,2 S0 S! S0 f& p8 T; {6 U+ {: Z/ H0 j' W" y* y
0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
: }2 u# b& G& x# N' P: Ivoid delay_ms(uint Z)
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      uint x,y;
8 }7 x! ?; j7 y! H       for(x=Z;x>0;x--)
( x: A% c: q# {       for(y=110;y>0;y--);5 \) V; C6 A5 `
}3 c5 g% h$ p/ P. Z7 [5 i
/*****ÅäÖÃIICD¾Æ¬**********/# J7 r/ g0 M* V2 {* s% `& |
void delay()
/ Z) I9 B% m" o7 ], J( ^2 x! ~{
# |. z4 C2 C, c- g) d4 J& d( _1 _       _nop_();_nop_();_nop_();_nop_();_nop_();_nop_();_nop_();_nop_();0 p) [) O9 b# p. X3 M' s0 I
}0 ]' H& x2 ?! g
void start()//¿aê¼* ?" J3 W8 ^: Q3 w% p) S$ q
{
  P( f& ^, V7 [0 }6 {       sda=1;( p6 V" x3 E# \$ n) O2 o
      delay();0 v9 K! L! A6 G$ j) c
      scl=1;
5 Q1 A8 E8 M+ v8 X$ X! L       delay();
' W1 R- `0 E& c' a9 l3 k4 q# _       sda=0;
$ B- H* u% F! j; C9 f/ @1 z6 j& ]' D; e       delay();
$ s, ~7 J( S: `8 @}
/ L& }3 U# l0 o9 @4 ^5 dvoid stop()
) s. `# ?+ w- A' i% i5 A{
* }& x- U5 k0 o3 @. V       sda=0;" [: j3 T0 S) |+ c% }. ~/ u* b
      delay();# X4 O% r2 [* ^0 V8 f. u
      scl=1;& c/ L% t  u2 r* \+ e
      delay();
& N3 B' O+ w1 A5 f       sda=1;
* d  @0 r5 ]0 k& \8 [# m       delay();
3 k; o) L- _% |8 u. j}
6 f: t+ \8 S* e8 }3 g3 evoid respons(); a) U! f* u+ M
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      uchar i;% s9 v9 J% _/ m: |+ v' U: |
      scl=1;3 v4 G' d1 S, G0 A9 b! U3 a
      delay();: k* M7 m% w! ^8 F& S% k6 z
      while((sda==1)&&(i<250)), Z6 _' u9 t8 W( D0 v2 s% @
            i++;  L' N4 Z1 i1 H; c5 Q
      scl=0;
# W6 Z. n2 s' c0 O! Z0 {; p# E       delay();
% F: r$ h: {3 H' ]+ W}
0 B3 X5 k. F- Rvoid init()7 ?, Z) J0 r6 L6 L# H5 e
{
, W) f9 p2 v. x# T1 @$ y$ S       sda=1;4 G5 [" ~/ u- }; N  I4 e! n8 q
      delay();
6 z9 @* ]' z! C       scl=1;
' p2 _: m' j) V9 ]; G# u- Z9 {: F       delay();
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void write_byte(uchar date)
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      uchar i,temp;
9 f4 L$ A7 Y# s       temp=date;$ a2 A4 U* {$ \+ y$ v
      for(i=0;i<8;i++)
. L' n$ X# a  q7 Y       {& k/ ?1 {; t: g3 F' Y- i9 J6 F
            temp=temp<<1;( n0 N+ e2 T8 w
            scl=0;4 p8 B% }" T2 s# L- d
            delay();
0 S0 Y# W+ J' }7 _# E             sda=CY;3 @! O# g; w1 G3 _& t& A
            delay();$ @- p/ w/ N- E: F- E+ U6 r; l
            scl=1;: _: v- a9 _% A9 ?0 c+ \. d5 j" y, p
            delay();9 ^' l9 w4 B$ r& ^
      }$ G7 J  r8 U  {# A; v
      scl=0;0 W2 o) F, I* b' l' Z0 G- r) \
      delay();4 [2 ^" j, l- a7 B- B3 }1 ?
      sda=1;
7 g& D7 Q* r5 c1 s3 I       delay();       ' |0 \$ R8 E4 S
}
; T: ~" F' @$ p; D! buchar read_byte(); }3 E9 @7 G) z2 T5 `7 L: D& i6 d
{) M- I5 |7 u2 o# n2 W
      uchar i,k;' F! ^3 `- G. {, Z
      scl=0;
: O! `" g+ ?9 H6 T  }/ {4 o  ~& h       delay();1 \/ _' C! c0 v' y: p+ a5 A+ S/ O" L
      sda=1;
/ I9 w4 D/ ~8 I  F0 k& ~       delay();! h7 V0 o- ~% @$ }
      for(i=0;i<8;i++)
. i% j/ J% g. w' s  ?       {( H' X. ?1 b5 t+ Z+ w0 K
            scl=1;
( O+ G: y1 x7 U) q) X; a# P             delay();
- g3 k/ N) F, p; W0 Z# H9 N! M       k=(k<<1)|sda;///////
2 b) C8 ?; X# Y( z8 [; w! d             scl=0;
) w& \5 H6 h  ?6 A' L! }' d             delay();/ n, r! i* G1 x/ \
      }3 y/ h# Y: e" H6 S6 ~5 A
      return k;* R/ ]; P: E% e& ?" j* ^& E4 z
}
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void write_add(uchar address,uchar date)
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      start();) L. ?: s4 U( @% a1 L5 r" D
      write_byte(0xa0);' f! S& r2 F- x" K+ k; E
      respons();" U: u7 b/ V! N; h' O9 Q: p
      write_byte(address);
" O; v+ Y8 g8 t' S- V       respons();& [7 f2 X/ o( o0 w4 f0 @
      write_byte(date);
/ U2 \* z# a/ m& J9 P  b2 Y% Y1 Q       respons();
3 {/ ]! _- E/ s+ X3 |* ]       stop();/ Z2 c. o  ]' k- O
}
% G- H" c4 P/ s2 Xuchar read_add(uchar address)
  V; s1 f2 |. ~" B- r{( V9 u6 {) C/ h
      uchar date;
6 h8 B* a# c1 {; {* o       start();5 g. Z# n- E+ ^/ w
      write_byte(0xa0);
  S# n# S7 P7 B9 a' }0 W       respons();
# T8 j! G$ e( `2 c) a$ D9 \& v' M       write_byte(address);7 u1 J( |4 V, C! n5 M, q' _
      respons();# J0 w. I( g. w6 l
      start();  z6 L; ]+ q- Y# S* Z# y
      write_byte(0xa1);
1 L9 O# ^" T8 W1 P, K& ^       respons();, T. j  A6 ~7 c- {( J
      date=read_byte();7 d7 M0 ~# r6 \" Z& I7 F8 p
      stop();4 P6 Q! [+ C" t5 p+ i3 j
      return date;0 S/ b2 B* L4 O
}
7 q; e! J! l8 s# F# D( F/************êyÂë1üÏÔê¾oˉêy*********************/8 ~9 f3 F. U/ U' p
void display(uchar shi,uchar ge)
, x/ ~2 o6 W8 ?6 r+ f, [{
! \$ R7 Q7 _; |: L# U       P1=0xdf;
% F: X5 `  w+ F& m3 h       P0=table[shi];0 i, n! N5 g7 Y; I  ]
      delay_ms(5);
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2 d, }4 U1 n2 Q       P1=0xef;
4 U+ U) v/ U, {% _       P0=table[ge];
, u1 B! l3 m$ U& e. p: {       delay_ms(5);. V+ q; k! \8 J( w# g$ l  S6 `, J3 @& @

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# B7 y0 a+ y% y9 e5 l$ Z% _5 U}
9 _& F9 x8 S- L& M* `( q, F/*********Ö÷oˉêy************************/
8 w4 U( }7 i; lvoid main()
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      init();4 D; t7 P# w% Z& h* `5 ^  M8 i6 g0 {% }
      num1=read_add(2);
$ _. r4 U2 {' z: L! U& k       if(num1>100); @8 U4 G/ {) e( t
            num1=0;
4 L! Y, `$ o6 C" E6 L2 v       TMOD=0x01;7 C  J6 A5 T! P: u; H
      TH0=(65536-50000)/256;
4 N' v3 H- \* u- P0 m) x       TL0=(65536-50000)%256;7 h7 S8 [$ P1 F$ c. F0 t$ m9 h& W
      ET0=1;
0 V2 Y  S: d' ?6 B8 l' ~6 Z/ e' C, O       EA=1;1 `" m# u- c4 M4 l# u8 y. ~. N
      TR0=1;
% c- K4 d/ i' N8 K# m2 T( j       while(1)
: \/ Z/ i+ ~6 _       {
# K! O) g9 P7 @# E: Q! U             display(num1/10,num1%10);0 c+ M8 b) v. \$ X8 j$ n
            if(write==1)
6 c- e. B8 }$ i/ y3 p; B  h             {2 L2 v. R0 i- F5 h
                     write=0;; U" S5 y! g$ y2 d3 A* X* B
                     write_add(2,num1);
& ]. p6 F5 g- ~5 ]3 o             }# X9 A7 t4 m$ T3 P0 ^9 y% [) \
      }5 C+ s5 Q+ T. A; j
}
+ b  ?; t9 E& M$ h8 x/*******ÖD¶Ïoˉêy*****************************/  i0 B$ {& i9 }$ U/ H
void time0() interrupt 1
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      TH0=(65536-50000)/256;
" C4 e  v1 B) \7 I# K* O       TL0=(65536-50000)%256;
* C1 m3 C& L* k4 W* C  A       num++;9 i8 k( |0 I7 O" A+ q/ K0 G
      if(num==20)& F3 _8 a5 k) L* o" ~3 m- k" T6 ^: z
      {
6 K6 R* y/ U& O( D2 h9 R$ }             num=0;) p# |) I) F9 Y
            num1++;
' o( @3 C5 w) s7 a% \" y8 y3 w3 a# d! c             write=1;
5 N* X  N& i+ q: N             if(num1==100)
. V& H' b, j$ N                      num1=0;* R0 x1 S* n; f6 @0 z1 q
      }5 B/ T" z$ _0 d4 N8 H) K# m" X
}
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Mhza · 发表于 2019-1-4 18:11

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